x^2+4x=437

Solution for x^2+4x=437 equation:

x^2+4x=437

We move all terms to the left:

x^2+4x-(437)=0

a = 1; b = 4; c = -437;
Δ = b2-4ac
Δ = 42-4·1·(-437)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-42}{2*1}=\frac{-46}{2}
=-23
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+42}{2*1}=\frac{38}{2}
=19
$